If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15y^2-41y+12=0
a = 15; b = -41; c = +12;
Δ = b2-4ac
Δ = -412-4·15·12
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-31}{2*15}=\frac{10}{30} =1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+31}{2*15}=\frac{72}{30} =2+2/5 $
| 4m-5(3m+10)=124 | | 3-d=3+8-3d(3) | | 3/(2m+4)=(1/(m+2))-2 | | x/3-x/3=0 | | x-34=-22 | | 6x-8x/2=-x | | -11x+5=5-11x | | 13x+9/7=5 | | x/4+x/4=x/2 | | 4(m+7)+5(m+4)=-6 | | 5(4x+6)-5(-6x-8)=20 | | -8-2/3hh=6 | | x+4x=8x-3x-1 | | x^2+2.4x+4=0 | | 16+x=6x-2-2x | | |2x|-8=10 | | V-7=-15+2v | | 7m+6÷3-4m+2÷4=2m+1÷3-2 | | -2.5(4g-8)=0.5(4-2g) | | 2(2+7x)=83 | | 8x+3=5x-5 | | 7-x+3=9x | | 5h/4=h+8 | | .3x=-0.09 | | 1/2(x+1)1/4=2/3x-1/6+3/5 | | 13/12w+8=-7 | | 34x-28=10x-9 | | 1/20=x/5 | | 7x-25=2x+35 | | 71+25x=4 | | 71+4x=25 | | 25+4x=71 |